Difficulty: Medium
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
Example 1:
1 2
| Input: 1->2->3->3->4->4->5 Output: 1->2->5
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Example 2:
1 2
| Input: 1->1->1->2->3 Output: 2->3
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Solution
Language: Java
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class Solution { public ListNode deleteDuplicates(ListNode head) { if (head == null) { return null; } ListNode dummy = new ListNode(0); dummy.next = head; ListNode prev = dummy; int cur = 0; while(head != null) { if (head.next != null && head.val == head.next.val) { cur = head.val; while (head != null && head.val == cur) { head = head.next; } prev.next = head; } else { prev = head; head = head.next; } } return dummy.next; } }
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